Optimal. Leaf size=135 \[ \frac{a^2 (4 B+5 C) \sin (c+d x)}{3 d}+\frac{a^2 (5 B+4 C) \sin (c+d x) \cos ^2(c+d x)}{12 d}+\frac{a^2 (7 B+8 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{B \sin (c+d x) \cos ^3(c+d x) \left (a^2 \sec (c+d x)+a^2\right )}{4 d}+\frac{1}{8} a^2 x (7 B+8 C) \]
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Rubi [A] time = 0.306812, antiderivative size = 135, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.175, Rules used = {4072, 4017, 3996, 3787, 2635, 8, 2637} \[ \frac{a^2 (4 B+5 C) \sin (c+d x)}{3 d}+\frac{a^2 (5 B+4 C) \sin (c+d x) \cos ^2(c+d x)}{12 d}+\frac{a^2 (7 B+8 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{B \sin (c+d x) \cos ^3(c+d x) \left (a^2 \sec (c+d x)+a^2\right )}{4 d}+\frac{1}{8} a^2 x (7 B+8 C) \]
Antiderivative was successfully verified.
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Rule 4072
Rule 4017
Rule 3996
Rule 3787
Rule 2635
Rule 8
Rule 2637
Rubi steps
\begin{align*} \int \cos ^5(c+d x) (a+a \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^4(c+d x) (a+a \sec (c+d x))^2 (B+C \sec (c+d x)) \, dx\\ &=\frac{B \cos ^3(c+d x) \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{4 d}+\frac{1}{4} \int \cos ^3(c+d x) (a+a \sec (c+d x)) (a (5 B+4 C)+2 a (B+2 C) \sec (c+d x)) \, dx\\ &=\frac{a^2 (5 B+4 C) \cos ^2(c+d x) \sin (c+d x)}{12 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{4 d}-\frac{1}{12} \int \cos ^2(c+d x) \left (-3 a^2 (7 B+8 C)-4 a^2 (4 B+5 C) \sec (c+d x)\right ) \, dx\\ &=\frac{a^2 (5 B+4 C) \cos ^2(c+d x) \sin (c+d x)}{12 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{4 d}+\frac{1}{3} \left (a^2 (4 B+5 C)\right ) \int \cos (c+d x) \, dx+\frac{1}{4} \left (a^2 (7 B+8 C)\right ) \int \cos ^2(c+d x) \, dx\\ &=\frac{a^2 (4 B+5 C) \sin (c+d x)}{3 d}+\frac{a^2 (7 B+8 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^2 (5 B+4 C) \cos ^2(c+d x) \sin (c+d x)}{12 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{4 d}+\frac{1}{8} \left (a^2 (7 B+8 C)\right ) \int 1 \, dx\\ &=\frac{1}{8} a^2 (7 B+8 C) x+\frac{a^2 (4 B+5 C) \sin (c+d x)}{3 d}+\frac{a^2 (7 B+8 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^2 (5 B+4 C) \cos ^2(c+d x) \sin (c+d x)}{12 d}+\frac{B \cos ^3(c+d x) \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{4 d}\\ \end{align*}
Mathematica [A] time = 0.360068, size = 86, normalized size = 0.64 \[ \frac{a^2 (24 (6 B+7 C) \sin (c+d x)+48 (B+C) \sin (2 (c+d x))+16 B \sin (3 (c+d x))+3 B \sin (4 (c+d x))+84 B c+84 B d x+8 C \sin (3 (c+d x))+96 C d x)}{96 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.091, size = 154, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ( B{a}^{2} \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +{\frac{{a}^{2}C \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+{\frac{2\,B{a}^{2} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+2\,{a}^{2}C \left ( 1/2\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/2\,dx+c/2 \right ) +B{a}^{2} \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) +{a}^{2}C\sin \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.946342, size = 194, normalized size = 1.44 \begin{align*} -\frac{64 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{2} - 3 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2} - 24 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2} + 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{2} - 48 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{2} - 96 \, C a^{2} \sin \left (d x + c\right )}{96 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.494474, size = 213, normalized size = 1.58 \begin{align*} \frac{3 \,{\left (7 \, B + 8 \, C\right )} a^{2} d x +{\left (6 \, B a^{2} \cos \left (d x + c\right )^{3} + 8 \,{\left (2 \, B + C\right )} a^{2} \cos \left (d x + c\right )^{2} + 3 \,{\left (7 \, B + 8 \, C\right )} a^{2} \cos \left (d x + c\right ) + 8 \,{\left (4 \, B + 5 \, C\right )} a^{2}\right )} \sin \left (d x + c\right )}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.15471, size = 238, normalized size = 1.76 \begin{align*} \frac{3 \,{\left (7 \, B a^{2} + 8 \, C a^{2}\right )}{\left (d x + c\right )} + \frac{2 \,{\left (21 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 24 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 77 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 88 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 83 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 136 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 75 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 72 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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